Question

An oblong garden measures $60m$ by $55m$. From the center of each side, a path $2$ meters wide goes across to the center of the opposite side. FInd the area of the paths.

Answer 1

Given that the paths are $2m$ on each side and goes across to the center of the opposite side. So, basically we have on one side a rectangle of length $60m$ and breadth $2m$ whose area is $A_1=60\times 2=120m^2$ and on another side a rectangle of length $59m$ and breadth $2m$ whose area is $A_2=55\times 2=110m^2$

One important note, the area of the central part has been included twice so, it has to subtracted once from the total area.

$\therefore$ Total area $=120+110-(2\times 2)$

$=230-4$

$=226sq.m$

$\therefore$ Total area of the path $=226sq.m.$

Hence, solved.