Question

An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer.

Answer 1

As the height of the Observer is $1.5$

$AE=22-1.5=20.5$

In $△AED$

$\tan \theta =\frac{AE}{ED}=\frac{20.5}{20.5}=1\Rightarrow \theta ={45}^o$

Therefore, answer is ${45}^o$