An observer can see through a pin-hole at the top end of a thin rod of height is 3h and its radius h. When the beaker is filled with a liquid up to a height 2h, he can see the lower end of the rod. Then the refractive index of the liquid is:
A
52√2
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B
√52
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C
√32
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D
32
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Solution
The correct option is A52√2 μ2N=sinisinr=251√2=25×√21μωa=52√2