An observer moves towards a stationary source of sound of frequency n. The apparent frequency heard by him is 2n. If the velocity of sound in air is 332 m/sec, then the velocity of the observer is

166 m/sec

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664 m/sec

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332 m/sec

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1328 m/sec

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Solution

The correct option is C
332 m/sec

n' = n $(\frac{v + v_{0}}{v}) \Rightarrow 2 n = n (\frac{v + v_{0}}{v}) \Rightarrow \frac{v + v_{0}}{v} = 0$

$\Rightarrow v_{0} = v = 322 m / s e c$

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An observer moves towards a stationary source of sound of frequency n. The apparent frequency heard by him is 2n. If the velocity of sound in air is 332 m/sec, then the velocity of the observer is

The correct option is C 332 m/sec n' = n (v+v0v)⇒2n=n(v+v0v)⇒v+v0v=0 ⇒v0=v=322m/sec

The correct option is C
332 m/sec

n' = n $(\frac{v + v_{0}}{v}) \Rightarrow 2 n = n (\frac{v + v_{0}}{v}) \Rightarrow \frac{v + v_{0}}{v} = 0$

$\Rightarrow v_{0} = v = 322 m / s e c$