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Question

An observer moves towards a stationary source of sound with a speed (1/5)th of the speed of sound. The wavelength and frequency of the source emitted are λ and f, respectively. The apparent frequency and wavelength recorded by the observer are, respectively,

A
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B
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C
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D
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Solution

The correct option is A
Given that velocity of source vS = 0(because it is stationary). Velocity of observer v0=(15)v=0.2v (where v is the velocity of sound). Actual frequency of source is f and actual wavelength of source is λ. We know from the Doppler’s effect that the apparent frequency recorded, when the observer is moving towards the stationary source, is given by
n=(v+v0vvs)×n=(v+0.2vv0)×n=1.2vv×n=1.2n=1.2f
Since the source is stationary, therefore the apparent wavelength remains unchanged, i.e., λ

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