You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Intensity vs Photocurrent

An oil drop c...

Question

An oil drop carrying charge Q is held in equilibrium by a potential difference of $600 V$ between the horizontal plates. In order to hold another drop of twice the radius in equilibrium a potential drop of $1600 V$ had to be maintained. The charge on the second drop is:

\frac{Q}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 Q}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 Q

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $3 Q$
Force balancing (Electrostatic force $=$ weight)

$Q_{1} E = 4 / 3 π r^{3} ρ$ g
$Q_{2} E = 4 / 3 π 8 r^{3} ρ$ g
$600 / 1600 \times Q_{1} / Q_{2} = 1 / 8 \Rightarrow Q_{2} = 3 Q_{1}$

Suggest Corrections

Similar questions

Q. In Millikan's oil drop experiment an oil drop carrying a charge

Q

is held stationary by a potential difference

2400 V

between the plates. To keep a drop of half the radius stationary the potential difference had to be made

600 V

. What is the charge on the second drop:

Q. In Millikan’s oil drop experiment, an oil drop of radius

r

and charge

Q

is held in equilibrium between the plates of a charged parallel plate capacitor when the potential difference is

V

. To keep a drop of radius

2 r

and charge

2 Q

in equilibrium between the plates ,the potential difference required will be

In Millikan's oil drop experiment, an oil drop is held stationary by a potential difference of $400$ V. If another drop of double the radius, but carrying the same charge, is to be held stationary, find the potential difference required ?

Q. In Millikan's oil drop experiment, an oil drop is held stationary by a potential deference of 400 V. If another drop of double the radius, but carrying the same charge, is to be held stationary, the potential difference required will be

Q. Two horizontal plates charged with

+ q

and

- q

charges are having an area of

A

. A charged drop of oil is suspended in equilibrium position between the plates, then the charge on the oil drop will be :

Join BYJU'S Learning Program

An oil drop carrying charge Q is held in equilibrium by a potential difference of 600V between the horizontal plates. In order to hold another drop of twice the radius in equilibrium a potential drop of 1600V had to be maintained. The charge on the second drop is:

The correct option is D 3QForce balancing (Electrostatic force = weight)Q1E=4/3πr3ρgQ2E=4/3π8r3ρg600/1600×Q1/Q2=1/8⇒Q2=3Q1

An oil drop carrying charge Q is held in equilibrium by a potential difference of $600 V$ between the horizontal plates. In order to hold another drop of twice the radius in equilibrium a potential drop of $1600 V$ had to be maintained. The charge on the second drop is:

The correct option is D $3 Q$
Force balancing (Electrostatic force $=$ weight)

$Q_{1} E = 4 / 3 π r^{3} ρ$ g
$Q_{2} E = 4 / 3 π 8 r^{3} ρ$ g
$600 / 1600 \times Q_{1} / Q_{2} = 1 / 8 \Rightarrow Q_{2} = 3 Q_{1}$