An old lady covered a certain distance at some speed. Had she moved 6kmph faster, she would have taken 80 minutes less. If she had moved 4kmph slower, she would have taken 80 minutes more. What is the distance (in km)?

320 km

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200 km

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240 km

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280 km

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160 km

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Solution

The correct option is E
160 km

Let distance = x km and usual rate = y kmph.

Then $\frac{x}{y} - \frac{x}{y + 6} = \frac{80}{60}$ - (i)

And $\frac{x}{y - 4} - \frac{x}{y} = \frac{80}{60}$ - (ii)

On dividing (i) by (ii), we get, x = 160 km

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An old lady covered a certain distance at some speed. Had she moved 6kmph faster, she would have taken 80 minutes less. If she had moved 4kmph slower, she would have taken 80 minutes more. What is the distance (in km)?

The correct option is E 160 km Let distance = x km and usual rate = y kmph. Then xy−xy+6=8060 - (i) And xy−4−xy=8060 - (ii) On dividing (i) by (ii), we get, x = 160 km

The correct option is E
160 km

Let distance = x km and usual rate = y kmph.

Then $\frac{x}{y} - \frac{x}{y + 6} = \frac{80}{60}$ - (i)

And $\frac{x}{y - 4} - \frac{x}{y} = \frac{80}{60}$ - (ii)

On dividing (i) by (ii), we get, x = 160 km