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Question

An op-amp amplifier with slew rate of 10 V/μ sec has a voltage gain of 66.0206 dB. If this amplifier has to faithfully amplify the sinusoidal signal from 6 to 10 kHz without introducing any distortion, then the maximum value of input signal amplitude is __ mV.
  1. 79.57

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Solution

The correct option is A 79.57

Slow rate=dV0dt|max

Slow rate=AdV0dt=A.ddtAmsin(ωt)

Slow rate=AAmω

now, A=1066.020620=2000

10×106=2×103×Am×2π×10×103

Am=79.57 mV

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