An open box is made of 3cm thick. Its external length, breadth, and hights are 1.48 m, 1.16m, 8.3dm. Find the cost of painting the inner surface at 50 p per 100 $c m^{2}$

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Solution

Thickness of wood = 3 cm
External dimensions :
Length = 1.48 m = 148 cm
Breadth = 1.16 m = 116 cm
Height = 8.3 dm = 83 cm
Now,
Inner length = Outer length - twice width = 148 - 6= 142 cm
Breadth = 110 cm
Height = 80 cm [ since it is open box]
Area of inner surface = $2 (l b + b h + h l) - l b$
= $2 [142 \times 100 + 110 \times 80 + 80 \times 142] - [142 \times 110]$ = $55940$ sq. cm
Cost of painting inner surface = $R s .$ $\frac{50}{100} \times \frac{55940}{100}$ = $R s .$ $279.90$

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An open box is made of 3cm thick. Its external length, breadth, and hights are 1.48 m, 1.16m, 8.3dm. Find the cost of painting the inner surface at 50 p per 100 cm2

An open box is made of 3cm thick. Its external length, breadth, and hights are 1.48 m, 1.16m, 8.3dm. Find the cost of painting the inner surface at 50 p per 100 $c m^{2}$