An open bucket is in the form of a frustum of height 21 cm...radii of the upper and lower ends as 20 cm and10cm respectively.. find the cost of milk which can completely fill it @ the rate of 30Rs per litre..

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Solution

h=21cm r1=10cm r2=20cm

V=1/3 pieX h[r1Xr2 + r1^2 + r2^2]

=1/3X 22/7 X21 {200+100+400}

=22X700=15400cm3

1000cm3=1L

15400cm3=15.4L

cost= Rs. 15.4 X 30

=Rs. 462
(22/7=pie)

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An open bucket is in the form of a frustum of height 21 cm...radii of the upper and lower ends as 20 cm and10cm respectively.. find the cost of milk which can completely fill it @ the rate of 30Rs per litre..

h=21cm r1=10cm r2=20cm V=1/3 pieX h[r1Xr2 + r1^2 + r2^2] =1/3X 22/7 X21 {200+100+400} =22X700=15400cm3 1000cm3=1L 15400cm3=15.4L cost= Rs. 15.4 X 30 =Rs. 462 (22/7=pie)

h=21cm r1=10cm r2=20cm

V=1/3 pieX h[r1Xr2 + r1^2 + r2^2]

=1/3X 22/7 X21 {200+100+400}

=22X700=15400cm3

1000cm3=1L

15400cm3=15.4L

cost= Rs. 15.4 X 30

=Rs. 462
(22/7=pie)