An open carriage in goods train is moving with a uniform velocity of $10 m s^{- 1}$ . If the train adds water with zero velocity at the rate of $5 k g s^{- 1}$ then the additional force applied by the engine to maintain the same velocity of the train is:

0.5 N

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2.0 N

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50 N

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25 N

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Solution

The correct option is D $50 N$
Rate of change in momentum due to water being added:
$\frac{d p}{d t} = \frac{d (m v)}{d t} = \frac{d m}{d t} v = 5 \times 10 = 50$
$\Rightarrow F = \frac{d p}{d t} = 50 N$

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An open carriage in goods train is moving with a uniform velocity of 10ms−1. If the train adds water with zero velocity at the rate of 5kgs−1 then the additional force applied by the engine to maintain the same velocity of the train is:

The correct option is D 50NRate of change in momentum due to water being added:dpdt=d(mv)dt=dmdtv=5×10=50⇒F=dpdt=50N

An open carriage in goods train is moving with a uniform velocity of $10 m s^{- 1}$ . If the train adds water with zero velocity at the rate of $5 k g s^{- 1}$ then the additional force applied by the engine to maintain the same velocity of the train is:

The correct option is D $50 N$
Rate of change in momentum due to water being added:
$\frac{d p}{d t} = \frac{d (m v)}{d t} = \frac{d m}{d t} v = 5 \times 10 = 50$
$\Rightarrow F = \frac{d p}{d t} = 50 N$