1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# An open cubical container of side H is filled with a liquid up to height H4. Mass of liquid inside container is 'm' (neglect atmospheric pressure). When the container is moved with maximum possible acceleration without spilling water, what will be the magnitude of force applied by liquid on left wall parallel to plane of paper?

A
mg
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
2mg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
mg3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
2mg3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B 2mgVolume of liquid inside container is H34. When container is moved with maximum possible acceleration: So, volume of this triangular portion = H34 12H.x(H)=H34 ⇒x=H2 We know that, angle θ is given by: tan θ=ag=Hx=2 ⇒a=2g Force due to left wall is: F=Pressure×Area Now this pressure is varying from top to bottom, so we will take its average value from 0 to ρgH. F=(0+ρgH)2.H2=ρgH32 [m=ρ(H34)]F=2g(ρH34)=2mg

Suggest Corrections
2
Join BYJU'S Learning Program
Related Videos
Viscosity
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program