An open flask containing air is heated from 300 K to 500 K . What percentage of air will be escaped to the atmosphere, if pressure is keeping constant?

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Solution

The correct option is B 40
Given that:

$T_{1} = 300 K, T_{2} = 300 K$

Let $V_{1} = V$ , then $V_{2} = ?$

So, $V_{2} = \frac{V_{1} T_{2}}{T_{1}}$

$V_{2} = \frac{V \times T_{2}}{T_{1}}$

$= V \times \frac{500}{300}$

$V_{2} = \frac{5 V}{3}$

So, volume of air escaped = $(V_{2} - V_{1})$

$= (\frac{5 V}{3} - V)$

$= \frac{5 V - 3 V}{3}$

$V_{2} = \frac{2 V}{3}$

So, percentage of air escaped = $\frac{2 V}{3} \times 100 \times \frac{3}{5 V}$

$= 40 %$

So, the correct option is $B$ .

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