wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An open flask contains air at 27 C°. It must be heated to to expel one - fourth of the volume.

A
127 C°
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
123 C°
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
133 C°
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 127 C°
Let volume of flask = 1 L
Volume α number of moles initially (n1)
Volume of air expelled 14L14n1
Number of moles left in the flask = (n114n1)=34n1

Ideal gas equation:
P1V1=n1RT1 ...(i),P1V1=n2RT2 ...(ii)
(Since P and V of the flask are constant)
From Eqs. (i) and (ii)
n1T1=n2T2
n1×300=34n1T2
T2=300×43=400K=127 C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Ideal Gas Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon