An open flask contains air at 27^∘ C. To what temperature it must be heated to expel one-fourth of the volume?

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Solution

The correct option is B

Ideal gas equation:
P₁V₁=n₁RT₁ ...(i),
P1V1=n2RT2 ...(ii)
(Since P and V of the flask are constant)
From Eqs. (i) and (ii)
n1T1=n2T2
n1×300=34n1T2
T2=300×43=400K=127^∘ C

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