Question

An open flask contains air at $27$. To what temperature it must be heated to expel one-fourth of the air?

Answer 1

According to Charles law:-

T id directly proportion to v

Thus $\frac{V_1}{V_2}=\frac{T_1}{T_2}$

$\frac{1}{.75}=\frac{300}{T_2}$

(let volume at initial volume at initial is 1 and after 27^0 temperature volume remains .75 of initial volume)

$T_2$=$225K$ or ${48}^0$