knife is dropped from A with u=0ms
From A and B
when it strikes the ground at B its velocity is:
v2−u2=2as
v2−0=2(g)(h)
v=√2gh
after striking the ground it travels a distance ′′d′′
in this case u=√2gh
v=0
s=d
therefore, v2−u2=2as
0−2gh=2(a)(d)
a=−ghd
Now, force applied by the ground is =ma=m(−ghd)=−m2gh2d