An open lift is moving upwards with a velocity of 10 metre per second the it is upward acceleration of 2 metre per second square A ball is projected upward with a velocity of 20 metre per second relative to the ground find the time when ball again meets the lift

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Dear Student ,
$h e i g h t c o v e r d b y b o t h w i l l b e s a m e s o l e t a g a i n m e e t i n g t i m e i s t 10 t + \frac{1}{2} \times 2 \times t^{2} = 20 t - \frac{1}{2} \times 10 \times t^{2} t = \frac{10}{6} = 1.66 s$
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An open lift is moving upwards with a velocity of 10 metre per second the it is upward acceleration of 2 metre per second square A ball is projected upward with a velocity of 20 metre per second relative to the ground find the time when ball again meets the lift

Dear Student , height coverd by both will be same so let again meeting time is t 10t+12×2×t2=20t-12×10×t2t=106=1.66s Regard

Dear Student ,
$h e i g h t c o v e r d b y b o t h w i l l b e s a m e s o l e t a g a i n m e e t i n g t i m e i s t 10 t + \frac{1}{2} \times 2 \times t^{2} = 20 t - \frac{1}{2} \times 10 \times t^{2} t = \frac{10}{6} = 1.66 s$
Regard