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Question

An open lift is moving upwards with velocity 10 m/s. It has an upward acceleration of 2 m/s2. A ball is projected upwards with velocity 20 m/s relative to ground. Find the time when ball again meets the lift.

A
43 s
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B
53 s
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C
54 s
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D
None
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Solution

The correct option is B 53 s
At the time when ball again meets the lift, sL=sB
10t+12×2×t2=20t12×10t2
Solving this equation, we get
Ball will again meet the lift after 53 s.

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