The correct option is
B 41cmFundamental frequency of an open organ pipe is given by , n1=v/λ=v/2l ,
where v=speed of sound in air (=330m/s),
λ= wavelength ,
l= length of organ pipe ,
given , n1=300Hz
therefore , n1=330/(2l) ,
or l=330/(2n1)=330/(2×300)=0.55m ,
now given , first overtone of open pipe =first overtone of closed pipe ,
v/l=3v/4l′ , where l′= length of closed pipe ,
or l′=3l/4=3×0.55/4=0.4125m=41.25cm