An open organ pipe has a length of 5 cm. (a) Find the fundamental frequency of vibration of this pipe. (b) What is the highest harmonic of such a tube that is in the audible range ? Speed of sound in air is 340ms−1 and the audible range is 20-20,000 Hz.
(a)Here given,
I=5cm=5×10−2m
v=340 m/s
⇒n=V2I=3402×5×10−2
=3.4 kHz
(b)If the fundamental frequency =3.4 kHz
Then the highest Harmonic in the audible range (20 Hz -20 kHz)
=20,0003400=5.8=5
(Integral multiple of 3.4 kHz)