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Conduction Law

An open pipe ...

Question

An open pipe immersed in water to half its length. The ratio of the fundamental frequency of the pipe before and after immersion in water is:

A

1 : 2

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B

1 : 1

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C

1 : 3

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D

1 : 4

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Solution

The correct option is C $1 : 1$
$l_{c} = \frac{l_{0}}{2}$
$\Rightarrow \frac{f_{0}}{f_{c}} = \frac{\frac{v}{2 l_{0}}}{\frac{v}{4 l_{c}}} = \frac{4 (\frac{l_{0}}{2})}{2 l_{0}} = 1$

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