An open pipe is suddenly closed at one end. As a result the frequency of third harmonic of the closed pipe is found to be higher by 100 Hz than the fundamental frequency of the open pipe. The fundamental frequency of open pipe is

200 Hz

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Solution

The correct option is A 200 Hz
$\frac{3 v}{4 l} - \frac{v}{2 l} = 100$
$\Rightarrow \frac{v}{4 l} = 100$
$\Rightarrow \frac{v}{2 l} = 200 H z$

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Q. An open pipe is suddenly closed at one end as a result of which the frequency of the third harmonic of the closed pipe is found to be higher by

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An open pipe is suddenly closed at one end and with the result frequency of third harmonic of the closed pipe is found to be higher by 100 Hz than the fundamental frequency of the open pipe. What is the fundamental frequency of the open pipe?

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An open pipe is suddenly closed at one end. As a result the frequency of third harmonic of the closed pipe is found to be higher by 100 Hz than the fundamental frequency of the open pipe. The fundamental frequency of open pipe is

The correct option is A 200 Hz3v4l−v2l=100 ⇒v4l=100 ⇒v2l=200Hz

The correct option is A 200 Hz
$\frac{3 v}{4 l} - \frac{v}{2 l} = 100$
$\Rightarrow \frac{v}{4 l} = 100$
$\Rightarrow \frac{v}{2 l} = 200 H z$