An open pipe is suddenly closed at one end with the result that frequency of third harmonic of the closed pipe is found to be higher by 150 Hz than the fundamental frequency of the open pipe. The fundamental frequency of the open pipe is:

200 Hz

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300 Hz

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240 Hz

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480 Hz

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Solution

The correct option is B 300 Hz
$3^{r d}$ harmonic of closed pipe; $f_{1} = \frac{3 v}{4 l}$
Fundamental of open pipe; $f_{2} = \frac{v}{2 l}$
$Δ f = f_{1} - f_{2} = 150 H z$

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An open pipe is suddenly closed at one end with the result that frequency of third harmonic of the closed pipe is found to be higher by 150 Hz than the fundamental frequency of the open pipe. The fundamental frequency of the open pipe is:

The correct option is B 300 Hz3rd harmonic of closed pipe; f1=3v4l Fundamental of open pipe; f2=v2l Δf=f1−f2=150Hz

The correct option is B 300 Hz
$3^{r d}$ harmonic of closed pipe; $f_{1} = \frac{3 v}{4 l}$
Fundamental of open pipe; $f_{2} = \frac{v}{2 l}$
$Δ f = f_{1} - f_{2} = 150 H z$