Question

An open pipe of length 24 cm is in resonance with a frequency 660 Hz. The radius of pipe is : (V=330 ms${}^{-1}$)

• A. 3 cm
• B. 0.83 cm
• C. 3.5 cm
• D. 2 cm

Answer 1

Answer: (B)

0.83 cm

Wavelength, $\lambda =\frac{V}{f}=\frac{330}{660}=0.5m$

By taking end correction:

$\frac{\lambda }{2}+0.6r=l$

$0.25-0.6r=24$

$0.6r=1cm$

$r=\frac{1}{0.6}=0.83cm$