An open pipe of length 33 cm resonates with frequency of 1000 Hz. If the speed of sound s 330 ms−1, then this frequency is
A
The fundamental frequency of the pipe'
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B
The first harmonic of the pipe
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C
The second harmonic of the pipe
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D
The forth harmonic of the pipe
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Solution
The correct option is C The second harmonic of the pipe Fundamental frequency (first harmonic frequency) of an open organ pipe is given by ,
n1=v/λ=v/2l ,
where v=speed of sound in air (=330m/s,given),
λ= wavelength ,
l= length of organ pipe (=33cm=0.33m , given) ,
therefore , n1=330/(2×0.33)=500Hz ,
as an open pipe produces even and odd harmonics , and given frequency is 1000Hz , it is 2 times of the first harmonic frequency , therefore it is second harmonic frequency of the pipe .