wiz-icon
MyQuestionIcon
MyQuestionIcon
8
You visited us 8 times! Enjoying our articles? Unlock Full Access!
Question

An open pipe of length 33 cm resonates with frequency of 1000 Hz. If the speed of sound s 330 ms−1, then this frequency is

A
The fundamental frequency of the pipe'
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
The first harmonic of the pipe
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
The second harmonic of the pipe
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
The forth harmonic of the pipe
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C The second harmonic of the pipe
Fundamental frequency (first harmonic frequency) of an open organ pipe is given by ,
n1=v/λ=v/2l ,
where v=speed of sound in air (=330m/s,given),
λ= wavelength ,
l= length of organ pipe (=33cm=0.33m , given) ,
therefore , n1=330/(2×0.33)=500Hz ,
as an open pipe produces even and odd harmonics , and given frequency is 1000Hz , it is 2 times of the first harmonic frequency , therefore it is second harmonic frequency of the pipe .

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Building a Wave
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon