Question

An open rectangular tank 1.5 m wide 2 m deep and 2m long is half filled with water. It is accelerated horizontally at 3.27 $m/se{c}^2$ in the direction of its length. Determine the depth of water at each end of tank. [g = 9.81 $m/se{c}^2$]

• A. 3.5 m
• B. 1.5 m
• C. 5 m
• D. 2.5 m

Answer 1

The correct option is B 1.5 m

Dimension of the tank$=2\times 1.5\times 2;a=3.27m{s}^{-2}$
tan $\theta =\frac{a}{g}=\frac{1}{3}$
Depth at corner 'A'
$=$ 1 - 1.5 tan $\theta$
$=$ 0.5 m
depth at corner 'B'
$=$ 1 + 1.5 tan $\theta$ $=$ 1.5 m