An open tank filled with water density - has a narrow hole at a depth of h below- then the velocity of water flowing out is-

The correct option is C √(2gh) From Bernoulli's equation, we can write: ρ g h=12ρ v^2 So, v=√(2gh) ...

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Standard XII

Physics

Bernoulli's Principle

An open tank ...

Question

An open tank filled with water density $ρ$ has a narrow hole at a depth of $h$ below, then the velocity of water flowing out is:

h ρ g

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2 g h

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\sqrt{2 g h}

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g h

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Solution

The correct option is C $\sqrt{2 g h}$
From Bernoulli's equation, we can write:
$ρ g h = \frac{1}{2} ρ v^{2}$
So, $v = \sqrt{2 g h}$

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An open tank filled with water density ρ has a narrow hole at a depth of h below, then the velocity of water flowing out is:

The correct option is C √2ghFrom Bernoulli's equation, we can write:ρgh=12ρv2So, v=√2gh

An open tank filled with water density $ρ$ has a narrow hole at a depth of $h$ below, then the velocity of water flowing out is:

The correct option is C $\sqrt{2 g h}$
From Bernoulli's equation, we can write:
$ρ g h = \frac{1}{2} ρ v^{2}$
So, $v = \sqrt{2 g h}$