An open tank is $3 m$ long and $2 m$ wide and $1 m 50 c m$ deep. Find the amount of paint required to paint its inside and outside, if $1 k g$ of paint covers $20$ square metre.

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Solution

Given: Length $= 3 m$
Breadth $= 2 m$
and, Height $= 1 m 50 c m = 1.5 m$
$∵$ We don't have to paint top of tank as it is an open tank.
Area of the tank (Cuboidal in shape) to be painted $= l b + 2 b h + 2 l h$
$= (3 \times 2) + (2 \times 2 \times 1.5) + (2 \times 3 \times 1.5) m m^{2}$
$= 6 + 6 + 9 = 21 m^{2}$
If $20 m^{2}$ requires $1 k g$ paint.
then $1 m^{2}$ will require $\frac{1}{20} k g$ paint.
So, $21 m^{2}$ will require $\frac{1}{20} \times 21 = \frac{20}{21} k g = 1.05 k g$ paint

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An open tank is 3 m long and 2 m wide and 1 m 50 cm deep. Find the amount of paint required to paint its inside and outside, if 1 kg of paint covers 20 square metre.

An open tank is $3 m$ long and $2 m$ wide and $1 m 50 c m$ deep. Find the amount of paint required to paint its inside and outside, if $1 k g$ of paint covers $20$ square metre.