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Acceleration Due to Gravity

An open tank ...

Question

An open tank of cross sectional area $A_{0}$ is filled with a liquid. A small orifice of area $A (A << A_{0})$ is present at the bottom of tank. At a moment the height of liquid in the tank is $H$ . What is the velocity of top layer of liquid at this moment?

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Solution

The velocity of top layer = $\frac{A}{A_{0}}$ velocity at hole
= $\frac{A}{A_{0}} \sqrt{2 g h}$

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