An open topped freight car of mass $10, 000 k g$ is coasting without friction along a level track in heavy rains, falling vertically downwards. Initially the car is empty and is moving with a velocity of $0.88 m / s$ . What is the velocity of the car after it has collected $1000 k g$ of water?

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Solution

R.E.F image
Let us take
final velocity of car be V
There is no friction between car and
Surface and no force acting in
horizontal direction on car
$\Rightarrow$ Momentum will be conserve
$(M o m e n t u m)_{i n i t i a l} = (m o m e n t u m)_{f i n a l}$
$m V_{0} = (m + m) u$
$10000 \times 0.88 = 11000 u$
$u = \frac{10000 \times 0.88}{11000}$
$u = 0.8 m^{- 1}$

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