Question

An operation $\lambda$ is defined for all real numbers $a$ and $b$ by the equation $a$ $\lambda$ $b=$ $\frac{a^2}{2}+\frac{b}{3}$. If $-3$ $\lambda$ $x=0$, find the value of $x$.

• A. -13.5
• B. -9
• C. 0
• D. 3
• E. 9

Answer 1

The correct option is A -13.5

Given $a\lambda b=\frac{a^2}{2}+\frac{b}{3}$ ,

Now put $a=-3$ and $b=x$

Then we get $-3\lambda x=-\frac{9}{2}+\frac{x}{3}=0$ , which implies $x=-\frac{27}{2}=-13.5$.