An optical fiber communication system works on a wavelength of 1-3 - m- The number of subscribers it can feed if a channel requires 20 kHz are A- 2-3 - 1010B- 1 - 105C- None of theseD- 1-15 - 1010

The correct option is D 1.15 X 1010Optical source frequency f = c/λ = 3 ×10^8/1.3 ×10^ 6 = 2.3 ×10^14 Hz ∴ Number of channels or subscribers = 2.3 ×10^14/20 ×1 ...

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Standard XII

Physics

Propagation of Waves

An optical fi...

Question

An optical fiber communication system works on a wavelength of 1.3 $μ$ m. The number of subscribers it can feed if a channel requires 20 kHz are

2.3 X 10¹⁰

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1.15 X 10¹⁰

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1 X 10⁵

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None of these

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Solution

The correct option is B 1.15 X 10¹⁰
Optical source frequency f = $\frac{c}{λ} = \frac{3 \times 10^{8}}{1.3 \times 10^{- 6}} = 2.3 \times 10^{14}$ Hz
$∴$ Number of channels or subscribers = $\frac{2.3 \times 10^{14}}{20 \times 10^{3}}$
= 1.15 $\times 10^{10}$

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An optical fiber communication system works on a wavelength of 1.3 μm. The number of subscribers it can feed if a channel requires 20 kHz are

The correct option is B 1.15 X 1010Optical source frequency f = cλ=3×1081.3×10−6=2.3×1014 Hz ∴ Number of channels or subscribers = 2.3×101420×103 = 1.15 ×1010

An optical fiber communication system works on a wavelength of 1.3 $μ$ m. The number of subscribers it can feed if a channel requires 20 kHz are

The correct option is B 1.15 X 10¹⁰
Optical source frequency f = $\frac{c}{λ} = \frac{3 \times 10^{8}}{1.3 \times 10^{- 6}} = 2.3 \times 10^{14}$ Hz
$∴$ Number of channels or subscribers = $\frac{2.3 \times 10^{14}}{20 \times 10^{3}}$
= 1.15 $\times 10^{10}$