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Question
An optically active compound A upon acid catalysed hydrolysis yield two optically active compound B and C by pseudo first order kinetics. The observed rotation of the mixture after 20 min was 20∘ while after completion of the reaction it was −20∘. If optical rotation per mole of A,B &C are 60∘,40 ∘& −80∘.Calculate half life of the reaction.
An optically active compound A upon acid catalysed hydrolysis yield two optically active compound B and C by pseudo first order kinetics. The observed rotation of the mixture after 20 min was 20∘ while after completion of the reaction it was −20∘. If optical rotation per mole of A,B &C are 60∘,40 ∘& −80∘.Calculate half life of the reaction.
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Solution
The correct option is A 20 min
As after completion of the reaction rotation is −20∘
So according to first order reaction
k=2.303log(r0−r∞)/(rt−r∞)/20=2.303log(80/40)/20
t1/2=0.693/k=20min
As after completion of the reaction rotation is −20∘
So according to first order reaction
k=2.303log(r0−r∞)/(rt−r∞)/20=2.303log(80/40)/20
t1/2=0.693/k=20min
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