An optically active hydrocarbon(X) on catalytic hydrogenation gives an optically inactive compound (Y), C6H14. The hydrocarbon (X) is-
A
3-methyl-1-pentene
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B
3-methyl-2-pentene
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C
2-ethyl-1-butene
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D
3-methylcyclopentene
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Solution
The correct option is A 3-methyl-1-pentene The optically active hydrocarbon X is 3-methyl-1-pentene CH2=CH−CH(CH3)CH2CH3. On catalytic hydrogenation, it forms, 3-methyl pentane CH3CH2CH(CH3)CH2CH3, which is optically inactive.