An orange precipitate of II group is dissolved in $c o n c . H C l$ ; the solution when treated with excess of water turns milky due to formation of :

S n (O H) C l

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S b (O H) C l_{2}

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S b O C l

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S b {(O H)}_{2} C l_{2}

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Solution

The correct option is C $S b O C l$
Option (C) is correct.
$S b O C l$ is formed.
$S b_{2} S_{3} + 6 H C l ⟶ 2 S b C l_{3} + 3 H_{2} S$ .
$S b C l_{3} + H_{2} O ⟶ S b O C l + 2 H C l$ .

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An orange precipitate of II group is dissolved in conc.HCl; the solution when treated with excess of water turns milky due to formation of :

The correct option is C SbOClOption (C) is correct.SbOCl is formed.Sb2S3+6HCl⟶2SbCl3+3H2S.SbCl3+H2O⟶SbOCl+2HCl.

An orange precipitate of II group is dissolved in $c o n c . H C l$ ; the solution when treated with excess of water turns milky due to formation of :

The correct option is C $S b O C l$
Option (C) is correct.
$S b O C l$ is formed.
$S b_{2} S_{3} + 6 H C l ⟶ 2 S b C l_{3} + 3 H_{2} S$ .
$S b C l_{3} + H_{2} O ⟶ S b O C l + 2 H C l$ .