An orbit is occupied by an electron with the quantum numbers $n = 4, l = 1.$ How many orbitals of this type are found in a multielectron atom.

4p, 3

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4s, 1

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4d, 5

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4p, 6

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Solution

The correct option is B 4p, 3
Here $n = 4, l = 1$
Then m = -1, 0, 1 and S = ±½
So possible orbitals are 3
Hence option A is correct

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Similar questions

(i) n = 4, m_{s} = - \frac{1}{2}

(i i) n = 3, l = 0

(i i i) n = 2, l = 1

(i v) n = 2, l = 0

n = 4, m_{s} = - 1 / 2

n = 3, l = 0

How many electrons in an atom may have the following quantum numbers?
(a) n = 4, $m = - \frac{1}{2}$
(b) n = 3, l = 0

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