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Standard XII

Physics

Current Loop Is a Magnet?

An orbital el...

Question

An orbital electron in the ground state of hydrogen has magnetic moment $μ_{1}$ . This orbital electron is excited to $3^{r d}$ excited state by some energy transfer to the hydrogen atom. The new magnetic moment of the electron is $μ_{2}$ then

μ_{1} = 4 μ_{2}

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2 μ_{1} = μ_{2}

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16 μ_{1} = μ_{2}

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4 μ_{1} = μ_{2}

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Solution

The correct option is D $4 μ_{1} = μ_{2}$
Given
Magnetic moment of electron in hydrogen atom in ground state is
Magnetic moment of electron in hydrogen atom in third excited state is
Solution
For hydrogen atom
$μ_{n} = \frac{e u_{n} r_{n}}{2 π}$
Here $u_{n}$ is inversely proportional to n and $r_{n}$ is directly proprtional to $n^{2}$
Therefore $μ_{n}$ is directly proportional to n
$μ_{1} = 1$
$μ_{2} = 4$ third excited state n= 4
The correct option is D

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An orbital electron in the ground state of hydrogen has magnetic moment μ1. This orbital electron is excited to 3rd excited state by some energy transfer to the hydrogen atom. The new magnetic moment of the electron is μ2 then

An orbital electron in the ground state of hydrogen has magnetic moment $μ_{1}$ . This orbital electron is excited to $3^{r d}$ excited state by some energy transfer to the hydrogen atom. The new magnetic moment of the electron is $μ_{2}$ then