An orbital made of two lobes can have the following quantum numbers?

n = 2, l = 2, m = 0

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n = 3, l = 1, m = - 1

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n = 3, l = 2, m = 0

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n = 3, l = 3, m = - 3

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Solution

The correct option is B $n = 3, l = 1, m = - 1$
We can see for only $p$ orbitals number of lobes is 2 and value of $l$ for $p$ orbital is 1.
So option $B$ is correct.

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Similar questions

(1) n = 1, l = 0, m = 0

(2) n = 2, l = 1, m = -1

(3) n = 2, l = 1, m = +1

(4) n = 3, l = 2, m = +1

(5) n = 3, l = 2, m = 0

n = 4, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}

n = 3, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}

n = 3, l = 2, m_{l} = 0, m_{s} = + \frac{1}{2}

n = 3, l = 0, m_{l} = 0, m_{s} = - \frac{1}{2}

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