Question

An ore contains $12\%$ copper. How many kilograms of the ore are required to get $69kg$ of copper?

Answer 1

Given:

Weight of the copper$=69$ kg

percentage $=12\%$

Percentage of part $=\frac{\text{part}\times 100}{\text{whole}}$

$\Rightarrow \text{whole}=\frac{\text{part}\times 100}{\text{part percentage}}$

$=\frac{69\times 100}{12}$

$=\frac{6900}{12}$

$=575$

Hence, the required answer is $575$ kg