An organ has a length of 17 cm. If the speed of sound through the air inside is 340 m/s. Calculate the fundamental frequency of the pipes given that pipe closed at one end.

250 Hz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

500 Hz

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1,000 Hz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1,500 Hz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2,000 Hz

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 500 Hz
Given : $v = 340$ m/s $L = 17$ cm $= 0.17$ m
Fundamental frequency of organ pipe closed at one end $ν_{1} = \frac{v}{4 L} = \frac{340}{4 \times 0.17} = 500$ Hz

Suggest Corrections

Similar questions

Q. An open organ pipe has fundamental frequency of

300 Hz

. The first overtone of this organ pipe is same as the first overtone of a closed organ pipe. Find the length of the closed organ pipe?
[speed of sound in air

= 330 m/s

]

Q. An open organ pipe has fundamental frequency of

300 Hz

. The first overtone of this organ pipe is same as the first overtone of a closed organ pipe. Find the length of the closed organ pipe?
[speed of sound in air

= 330 m/s

]

Q. The first overtone of an open organ pipe beats with the first overtone of a closed organ pipe with a beat frequency of 2.2 Hz. The fundamental frequency of the closed organ pipe is 110 Hz. Find the lengths of the pipes. Speed of sound in air v = 330 m/s.

A closed pipe has length 0.6m. The air inside the pipe is maintained at temperature $27^{\circ} C$ . Calculate the fundamental frequency and the frequency of the next two overtones.
(given velocity of sound in air at $0^{\circ} C = 330 m s^{- 1}$ )

Q. An open organ pipe filled with air has a fundamental frequency 500Hz. The first harmonic of another organ pipe closed at one end and filled with carbon dioxide has the same frequency as that of the first harmonic of the open organ pipe. Calculate the length of each pipe. Assume that the velocity of sound in air and in carbondioxide to be 330 and 264 m/s respectively.

Join BYJU'S Learning Program

An organ has a length of 17 cm. If the speed of sound through the air inside is 340 m/s. Calculate the fundamental frequency of the pipes given that pipe closed at one end.

The correct option is B 500 HzGiven : v=340 m/s L=17 cm =0.17 mFundamental frequency of organ pipe closed at one end ν1=v4L=3404×0.17=500 Hz

The correct option is B 500 Hz
Given : $v = 340$ m/s $L = 17$ cm $= 0.17$ m
Fundamental frequency of organ pipe closed at one end $ν_{1} = \frac{v}{4 L} = \frac{340}{4 \times 0.17} = 500$ Hz