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Standard XII

Physics

Expression for Standing Waves

An organ pipe...

Question

An organ pipe $P_{1}$ closed at one end and vibrating its third harmonic, and another pipe $P_{2}$ , open at both ends and vibrating in its fourth harmonic, are in resonance with a given turning fork. The ratio of the length of $P_{1}$ to that of $P_{2}$ is:

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Solution

The correct option is B $3 / 8$
$\frac{3 V}{4 l_{C}} = \frac{4 V}{2 l_{0}}$

$\Rightarrow \frac{l_{C}}{l_{0}} = \frac{3}{8}$

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An organ pipe P1 closed at one end and vibrating its third harmonic, and another pipe P2, open at both ends and vibrating in its fourth harmonic, are in resonance with a given turning fork. The ratio of the length of P1 to that of P2 is:

The correct option is B 3/83V4lC=4V2l0⇒lCl0=38

An organ pipe $P_{1}$ closed at one end and vibrating its third harmonic, and another pipe $P_{2}$ , open at both ends and vibrating in its fourth harmonic, are in resonance with a given turning fork. The ratio of the length of $P_{1}$ to that of $P_{2}$ is:

The correct option is B $3 / 8$
$\frac{3 V}{4 l_{C}} = \frac{4 V}{2 l_{0}}$

$\Rightarrow \frac{l_{C}}{l_{0}} = \frac{3}{8}$