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Preparation of Chlorine

An organic co...

Question

An organic compound (A) on heating produces two gases (B) and (C) and neutral oxide (D) which turns cobalt chloride paper pink. Gas (B) turns lime water milky and produces an acidic solution, with water. Gas (C) produces a poisonous gas (E) with chlorine gas, this gas with ammonia gives an organic compound (F) which on further reaction with (D) gives $N H_{3}$ gas. Then, compounds (A) and (F) can be found as:

H_{2} C_{2} O_{4}

and

N H_{2} C O N H_{2}

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C H_{3} C O O H

and

N H_{2} C O N H_{2}

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C H C l_{3}

and

C H_{3} C O N H_{2}

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C H_{3} C l

and

N H_{2} C O O N H_{4}

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Solution

The correct option is A $H_{2} C_{2} O_{4}$ and $N H_{2} C O N H_{2}$
Reaction:
$H_{2} C_{2} O_{4} \to C O + C O_{2} + H_{2} O$
A- Oxalic acid

Carbon dioxide ( $C O_{2}$ ) turns lime water milky due to the formation of insoluble calcium carbonate, $C a C O_{3}$
B - $C O_{2}$

Cobalt ions are hydrated in the solution and have a pink colour.
D- $H_{2} O$

So, gas C is $C O$ which when reacts with $C l_{2}$ gives $C O C l_{2}$ which is poisonous gas.

$C O + C l_{2} \to C O C l_{2}$

$C O C l_{2} + 4 N H_{3} \to (N H_{2})_{2} C O + 2 N H_{4} C l$

F reacts with D gives $N H_{3}$ gas.

Reaction:
$(N H_{2})_{2} C O + H_{2} O \to 2 N H_{3} + C O_{2}$

Option A is correct.

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