An organic compound A on heating with concentrated H2SO4 nbsp-forms a compound B which on addition of one mole of hydrogen in the presence of Ni forms a compound nbsp-C- One mole of compound C- nbsp-One mole of compound C on combustion forms two moles of CO3 and three moles of H2O- Identify compounds A-B and C and write balanced chemical reactions for the reactions involved-

Since nbsp;H2SO4 nbsp;is a dehydrating agent, so it can remove water from the alcohol to form nbsp;alkene. Here we can see that compound B is undergoing h ...

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Standard XII

Chemistry

Multiple Bond Formation

An organic co...

Question

An organic compound A on heating with concentrated H₂SO₄forms a compound B which on addition of one mole of hydrogen in the presence of Ni forms a compound C. One mole of compound C. One mole of compound C on combustion forms two moles of CO₃ and three moles of H₂O. Identify compounds A,B and C and write balanced chemical reactions for the reactions involved.

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Solution

Since H₂SO₄is a dehydrating agent, so it can remove water from the alcohol to form alkene. Here we can see that compound B is undergoing hydrogenation that means it is unsaturated or alkene, also only 1 mole of H₂ is used , therefore only one double bond is present.
Compound C on combustion forming 2 mole of CO₂ and 3 mole of H₂O, suggesting that only 2 Carbon atom is present in parent alkane.
Therefore we can say that:
Compound A is alcohol, CH₃CH₂OH
Compound B is Alkene, CH₂=CH₂
Compound C is alkane , CH₃CH₃_.
And reaction can be written as:
1) CH₃CH₂OH $\overset{c o n c . H_{2} S O_{4}}{\to}$ CH₂=CH₂
2) CH₂=CH_{2 $\overset{N i / H_{2}}{\to}$} CH₃CH₃
3) 2CH₃CH₃ + 7O₂ $\to$ 4CO₂+ 6H₂O

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