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Question

An organic compound “A” on treatment with benzenesulfonyl chloride gives compound B. B is soluble in dil. NaOH solution. Compound A is:

A
C6H5N(CH3)2
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B
C6H5NHCH2CH3
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C
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D
C6H5CH2NHCH3
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Solution

The correct option is C
The benzenesulfonyl chloride is Hinsberg reagent.
This reagent is used to distinguish between primary, secondary and tertiary amine.
In this reaction, the amine acts as a nucleophile and attacks the electrophilic benzenesulfonyl chloride.
This reaction leads to the displacement of the chloride and the generation of the N- alkylbenzenesulfonamide. When the primary amine forms a sulfonamide, this product is soluble in aqueous sodium hydroxide (NaOH). On the contrary, secondary amine’s sulfonamide precipitates from the alkali solution as a solid.
Tertiary amines do not form any stable sulfonamides.
Thus, compound 'A' is a primary amine
Hence, option (c) is correct.


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