An organic compound 'A' on treatment with NH3 gives 'B', which on heating gives 'C'. 'C', when treated with Br2 in the presence of KOH, produces ethylamine. Compound 'A' is:
A
CH3CH2COOH
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B
CH3COOH
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C
CH3CH2CH2COOH
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D
CH3−CH(CH3)−COOH
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Solution
The correct option is ACH3CH2COOH When propanoic acid is reacted with liq.ammonia it gives 1-amino propanone and water as a byproduct
1-amino propanone is reacted with bromine in presence of potassium hydroxide, Hofmann bromamide reaction takes place which gives ethylamine as a product.
Thus Propanoic acid (CH3CH2COOH) is the correct answer.