An organic compound 'A' produces a gas with brisk effervescence when sodium bicarbonate is added to it. The compound 'A' contains same number of carbons as in ethane. The compound 'A' reacts with ethanol to form a sweet smelling compound 'C' in presence of conc. $H_{2} S O_{4}$ . A and C respectively are :

ethanoic acid and ethyl ethanoate

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methanoic acid and ethyl methanoate

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ethanoic acid and sodium ethanoate

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Solution

The correct option is B ethanoic acid and ethyl ethanoate
Ethanoic acid reacts with sodium bicarbonate, to form carbon dioxide which produces effervescence as:

$C H_{3} C O O H + N a H C O_{3} \to C H_{3} C O O N a + H_{2} O + C O_{2}$

Also, ethanoic acid reacts with ethanol to form the ester - ethyl ethanoate as follows:

$C H_{3} C O O H + C_{2} H_{5} O H c o n c . H_{2} S O_{4} ⟶ C H_{3} C O O C H_{2} C H_{3} + H_{2} O$

Thus, A is ethanoic acid and C is ethyl ethanoate.

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An organic compound 'A' produces a gas with brisk effervescence when sodium bicarbonate is added to it. The compound 'A' contains same number of carbons as in ethane. The compound 'A' reacts with ethanol to form a sweet smelling compound 'C' in presence of conc. H2SO4. A and C respectively are :