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Question

An organic compound A with molecular formula C5H11Br when treated with alc.KOH forms B which with H2O in H2SO4(dil) gives C.Compound C when treated with PBr3 gives D which is an isomer of A.
D with Na in dry ether gives E, structure of which is different when A reacts with Na.
Identify A,B,C,D,E. Write suitable chemical reactions to show the conversion. Write the IUPAC name of each of the compounds.

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Solution

​Dear Student,

Compound A is CH3CH2CH2CH2CH2Br i.e. 1-bromopentane CH3CH2CH2CH2CH2Br + alc. KOH CH3CH2CH2CH=CH2Therefore, B is Pent-1-eneCH3CH2CH2CH=CH2 H2SO4 H2OCH3CH2CH2CH(OH)CH3Therefore, C is Pentan-2-olCH3CH2CH2CH(OH)CH3 PBr3 CH3CH2CH2CH(Br)CH3D is 2-bromopentaneCH3CH2CH2CH(Br)CH3 dry ether Na CH3CH2CH2CH(CH3)CH(CH3)CH2CH2CH3E is 4,5-dimethyloctaneWhen A reats with Na :CH3CH2CH2CH2CH2Br dry ether Na CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3Here decane is formed.

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