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Ozonolysis

An organic co...

Question

An organic compound $C_{6} H_{12} (X)$ on reduction gives $C_{6} H_{14} (Y) . X$ on ozonolysis gives two aldehydes $C_{2} H_{4} O (I)$ and $C_{4} H_{8} O (I I)$ . Identify the compounds $X, Y$ and aldehydes $(I)$ and $(I I)$ .

A

X : C H_{3} C H = C H C H_{2} C H_{2} C H_{3}, Y : C H_{3} (C H_{2})_{4} C H_{3}, (I) C H_{3} C H O, (I I) C H_{3} (C H_{2})_{2} C H O

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B

X = C H_{3} C H_{2} C H = C H C H_{2} C H_{3}, Y : C H_{3} (C H_{2})_{4} C H_{3}, (I) C H_{3} C H O, (I I) C H_{3} C H O

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C

X : C H_{3} C H_{2} C H_{2} C H_{2} C H = C H_{2}, Y : C H_{3} (C H_{2})_{3} C H_{3}, (I) H C H O, (I I) C H_{3} (C H_{2})_{2} C H O

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D

X : C H_{3} C H_{2} - C | = C H_{3} C H - C H_{3}, Y : C H_{3} (C H_{2})_{3} C H_{3}, (I) C H_{3} C H O, (I I) C H_{3} C H_{2} C H O

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Solution

The correct option is A $X : C H_{3} C H = C H C H_{2} C H_{2} C H_{3}, Y : C H_{3} (C H_{2})_{4} C H_{3}, (I) C H_{3} C H O, (I I) C H_{3} (C H_{2})_{2} C H O$
$C H_{3} C H = C H C H_{2} C H_{2} C H_{3} (X) H_{2} - \to C H_{3} {(C H_{2})}_{4} C H_{3} (Y)$
Hence, option $A$ is correct answer.

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