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Question

An organic compound containing carbon, hydrogen and oxygen contains 52.20% carbon and 13.04% hydrogen. Vapour density of the compound is 23. Its molecular formula will be:

A
C2H6O
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B
C3H8O
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C
C4H8O
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D
C5H10O
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Solution

The correct option is D C2H6O
Percentage of O is 34.76.
C:H:O=52.2012:13.041:34.7616=4.33:13:2.15=2:6:1
Equivalent weight = 46
Molecular weight =2×23=46.
x=4646=1
Molecular formula=(Empirical formula)x
Molecular formula=C2H6O

So, the correct option is A

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